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1000103220131 is a prime number
BaseRepresentation
bin11101000110110101100…
…11000001001110100011
310112121102220122112212212
432203122303001032203
5112341202411021011
62043235134512335
7132153330052241
oct16433263011643
93477386575785
101000103220131
11356161216794
121419b06656ab
1373403798c42
1436596035791
151b03585508b
hexe8dacc13a3

1000103220131 has 2 divisors, whose sum is σ = 1000103220132. Its totient is φ = 1000103220130.

The previous prime is 1000103220097. The next prime is 1000103220211. The reversal of 1000103220131 is 1310223010001.

1000103220131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (1310223010001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000103220131 - 210 = 1000103219107 is a prime.

It is a super-2 number, since 2×10001032201312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1000103220331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500051610065 + 500051610066.

It is an arithmetic number, because the mean of its divisors is an integer number (500051610066).

Almost surely, 21000103220131 is an apocalyptic number.

1000103220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000103220131 is an equidigital number, since it uses as much as digits as its factorization.

1000103220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1000103220131 its reverse (1310223010001), we get a palindrome (2310326230132).

The spelling of 1000103220131 in words is "one trillion, one hundred three million, two hundred twenty thousand, one hundred thirty-one".