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100011002220193 is a prime number
BaseRepresentation
bin10110101111010110100000…
…010000101100111010100001
3111010002221212200221020001111
4112233112200100230322201
5101102040013032021233
6552412230430303321
730031361603363041
oct2657264020547241
9433087780836044
10100011002220193
1129959478521039
12b272976357b41
1343a5cc6669ccc
141a9a7b60dd721
15b867b064bacd
hex5af5a042cea1

100011002220193 has 2 divisors, whose sum is σ = 100011002220194. Its totient is φ = 100011002220192.

The previous prime is 100011002220169. The next prime is 100011002220203. The reversal of 100011002220193 is 391022200110001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97172612918689 + 2838389301504 = 9857617^2 + 1684752^2 .

It is an emirp because it is prime and its reverse (391022200110001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100011002220193 is a prime.

It is not a weakly prime, because it can be changed into another prime (100011002220163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005501110096 + 50005501110097.

It is an arithmetic number, because the mean of its divisors is an integer number (50005501110097).

Almost surely, 2100011002220193 is an apocalyptic number.

It is an amenable number.

100011002220193 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011002220193 is an equidigital number, since it uses as much as digits as its factorization.

100011002220193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 100011002220193 its reverse (391022200110001), we get a palindrome (491033202330194).

The spelling of 100011002220193 in words is "one hundred trillion, eleven billion, two million, two hundred twenty thousand, one hundred ninety-three".