Base | Representation |
---|---|
bin | 1001000110001001000010… |
… | …0111011011101001111011 |
3 | 1022102002121120010020200001 |
4 | 2101202100213123221323 |
5 | 2302324233142333313 |
6 | 33134240242453431 |
7 | 2051361555253024 |
oct | 221422047335173 |
9 | 38362546106601 |
10 | 10001110121083 |
11 | 32064a0a31464 |
12 | 1156347664277 |
13 | 577140140bc3 |
14 | 2680b0743c4b |
15 | 125242627add |
hex | 918909dba7b |
10001110121083 has 2 divisors, whose sum is σ = 10001110121084. Its totient is φ = 10001110121082.
The previous prime is 10001110121077. The next prime is 10001110121203. The reversal of 10001110121083 is 38012101110001.
10001110121083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10001110121083 - 233 = 9992520186491 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10001110121083.
It is not a weakly prime, because it can be changed into another prime (10001110121983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000555060541 + 5000555060542.
It is an arithmetic number, because the mean of its divisors is an integer number (5000555060542).
Almost surely, 210001110121083 is an apocalyptic number.
10001110121083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001110121083 is an equidigital number, since it uses as much as digits as its factorization.
10001110121083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 10001110121083 its reverse (38012101110001), we get a palindrome (48013211231084).
The spelling of 10001110121083 in words is "ten trillion, one billion, one hundred ten million, one hundred twenty-one thousand, eighty-three".
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