10001111001113 has 2 divisors, whose sum is σ = 10001111001114. Its totient is φ = 10001111001112.

The previous prime is 10001111001061. The next prime is 10001111001127. The reversal of 10001111001113 is 31110011110001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9296565646729 + 704545354384 = 3049027^2 + 839372^2 .

It is an emirp because it is prime and its reverse (31110011110001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10001111001113 - 2¹⁶ = 10001110935577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10001111001094 and 10001111001103.

It is not a weakly prime, because it can be changed into another prime (10001111001163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000555500556 + 5000555500557.

It is an arithmetic number, because the mean of its divisors is an integer number (5000555500557).

Almost surely, 2^{10001111001113} is an apocalyptic number.

It is an amenable number.

10001111001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001111001113 is an equidigital number, since it uses as much as digits as its factorization.

10001111001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 10001111001113 its reverse (31110011110001), we get a palindrome (41111122111114).

The spelling of 10001111001113 in words is "ten trillion, one billion, one hundred eleven million, one thousand, one hundred thirteen".