Base | Representation |
---|---|
bin | 1001000110001001000010… |
… | …1111011001101001111011 |
3 | 1022102002121201001101011221 |
4 | 2101202100233121221323 |
5 | 2302324234211210133 |
6 | 33134240355332511 |
7 | 2051361612103213 |
oct | 221422057315173 |
9 | 38362551041157 |
10 | 10001112210043 |
11 | 32064a2128979 |
12 | 11563482b1137 |
13 | 5771406c2986 |
14 | 2680b0b29243 |
15 | 1252428dba2d |
hex | 91890bd9a7b |
10001112210043 has 2 divisors, whose sum is σ = 10001112210044. Its totient is φ = 10001112210042.
The previous prime is 10001112209951. The next prime is 10001112210073. The reversal of 10001112210043 is 34001221110001.
10001112210043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10001112210043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10001112209999 and 10001112210026.
It is not a weakly prime, because it can be changed into another prime (10001112210073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000556105021 + 5000556105022.
It is an arithmetic number, because the mean of its divisors is an integer number (5000556105022).
Almost surely, 210001112210043 is an apocalyptic number.
10001112210043 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001112210043 is an equidigital number, since it uses as much as digits as its factorization.
10001112210043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10001112210043 its reverse (34001221110001), we get a palindrome (44002333320044).
The spelling of 10001112210043 in words is "ten trillion, one billion, one hundred twelve million, two hundred ten thousand, forty-three".
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