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10001113301 = 95731104471
BaseRepresentation
bin10010101000001110…
…01110000011010101
3221210222212012021202
421110013032003111
5130440241111201
64332222322245
7502560026504
oct112407160325
927728765252
1010001113301
1142724054a3
121b31429385
13c34cba12a
146ac37283b
153d802cc6b
hex2541ce0d5

10001113301 has 4 divisors (see below), whose sum is σ = 10001313504. Its totient is φ = 10000913100.

The previous prime is 10001113271. The next prime is 10001113307. The reversal of 10001113301 is 10331110001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10331110001 = 17607712353.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10001113301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10001113307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43496 + ... + 147966.

It is an arithmetic number, because the mean of its divisors is an integer number (2500328376).

Almost surely, 210001113301 is an apocalyptic number.

It is an amenable number.

10001113301 is a deficient number, since it is larger than the sum of its proper divisors (200203).

10001113301 is an equidigital number, since it uses as much as digits as its factorization.

10001113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200202.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 10001113301 its reverse (10331110001), we get a palindrome (20332223302).

The spelling of 10001113301 in words is "ten billion, one million, one hundred thirteen thousand, three hundred one".

Divisors: 1 95731 104471 10001113301