1000112112017 has 2 divisors, whose sum is σ = 1000112112018. Its totient is φ = 1000112112016.

The previous prime is 1000112112011. The next prime is 1000112112031. The reversal of 1000112112017 is 7102112110001.

1000112112017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 693649116736 + 306462995281 = 832856^2 + 553591^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000112112017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1000112111986 and 1000112112004.

It is not a weakly prime, because it can be changed into another prime (1000112112011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500056056008 + 500056056009.

It is an arithmetic number, because the mean of its divisors is an integer number (500056056009).

Almost surely, 2^{1000112112017} is an apocalyptic number.

It is an amenable number.

1000112112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000112112017 is an equidigital number, since it uses as much as digits as its factorization.

1000112112017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 1000112112017 its reverse (7102112110001), we get a palindrome (8102224222018).

The spelling of 1000112112017 in words is "one trillion, one hundred twelve million, one hundred twelve thousand, seventeen".