100012000111 has 4 divisors (see below), whose sum is σ = 103460689800. Its totient is φ = 96563310424.

The previous prime is 100012000097. The next prime is 100012000117. The reversal of 100012000111 is 111000210001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100012000111 - 2⁵ = 100012000079 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100012000094 and 100012000103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100012000117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1724344801 + ... + 1724344858.

It is an arithmetic number, because the mean of its divisors is an integer number (25865172450).

Almost surely, 2^100012000111 is an apocalyptic number.

100012000111 is a deficient number, since it is larger than the sum of its proper divisors (3448689689).

100012000111 is an equidigital number, since it uses as much as digits as its factorization.

100012000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3448689688.

The product of its (nonzero) digits is 2, while the sum is 7.

Adding to 100012000111 its reverse (111000210001), we get a palindrome (211012210112).

The spelling of 100012000111 in words is "one hundred billion, twelve million, one hundred eleven", and thus it is an aban number.