100012112113 has 4 divisors (see below), whose sum is σ = 102140029440. Its totient is φ = 97884194788.

The previous prime is 100012112069. The next prime is 100012112197. The reversal of 100012112113 is 311211210001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100012112113 - 2⁹ = 100012111601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100012112093 and 100012112102.

It is not an unprimeable number, because it can be changed into a prime (100012112713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1063958593 + ... + 1063958686.

It is an arithmetic number, because the mean of its divisors is an integer number (25535007360).

Almost surely, 2^100012112113 is an apocalyptic number.

It is an amenable number.

100012112113 is a deficient number, since it is larger than the sum of its proper divisors (2127917327).

100012112113 is an equidigital number, since it uses as much as digits as its factorization.

100012112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2127917326.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 100012112113 its reverse (311211210001), we get a palindrome (411223322114).

The spelling of 100012112113 in words is "one hundred billion, twelve million, one hundred twelve thousand, one hundred thirteen".