Base | Representation |
---|---|
bin | 10110101111010111100010… |
… | …111001000111110000010011 |
3 | 111010010001202121110000112012 |
4 | 112233113202321013300103 |
5 | 101102044310222042042 |
6 | 552412533402453135 |
7 | 30031431366325205 |
oct | 2657274271076023 |
9 | 433101677400465 |
10 | 100012120112147 |
11 | 299599a1546891 |
12 | b2730288041ab |
13 | 43a6144143739 |
14 | 1a9a880778775 |
15 | b86828868e82 |
hex | 5af5e2e47c13 |
100012120112147 has 2 divisors, whose sum is σ = 100012120112148. Its totient is φ = 100012120112146.
The previous prime is 100012120112131. The next prime is 100012120112183. The reversal of 100012120112147 is 741211021210001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100012120112147 - 24 = 100012120112131 is a prime.
It is not a weakly prime, because it can be changed into another prime (100012120412147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006060056073 + 50006060056074.
It is an arithmetic number, because the mean of its divisors is an integer number (50006060056074).
Almost surely, 2100012120112147 is an apocalyptic number.
100012120112147 is a deficient number, since it is larger than the sum of its proper divisors (1).
100012120112147 is an equidigital number, since it uses as much as digits as its factorization.
100012120112147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 100012120112147 its reverse (741211021210001), we get a palindrome (841223141322148).
The spelling of 100012120112147 in words is "one hundred trillion, twelve billion, one hundred twenty million, one hundred twelve thousand, one hundred forty-seven".
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