Base | Representation |
---|---|
bin | 101110100100101000… |
… | …0001000000101101110 |
3 | 100120011002111120201120 |
4 | 1131021100020011232 |
5 | 3114311340241024 |
6 | 113540114121410 |
7 | 10140264163332 |
oct | 1351120100556 |
9 | 316132446646 |
10 | 100013212014 |
11 | 3946293a521 |
12 | 17472280266 |
13 | 957b4872c1 |
14 | 4baaadd7c2 |
15 | 2905499479 |
hex | 174940816e |
100013212014 has 16 divisors (see below), whose sum is σ = 202436381952. Its totient is φ = 32936077688.
The previous prime is 100013212009. The next prime is 100013212043. The reversal of 100013212014 is 410212310001.
It is a junction number, because it is equal to n+sod(n) for n = 100013211984 and 100013212002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100414374 + ... + 100415369.
It is an arithmetic number, because the mean of its divisors is an integer number (12652273872).
Almost surely, 2100013212014 is an apocalyptic number.
100013212014 is an abundant number, since it is smaller than the sum of its proper divisors (102423169938).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100013212014 is a wasteful number, since it uses less digits than its factorization.
100013212014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 200829831.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 100013212014 its reverse (410212310001), we get a palindrome (510225522015).
The spelling of 100013212014 in words is "one hundred billion, thirteen million, two hundred twelve thousand, fourteen".
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