10001340211 has 4 divisors (see below), whose sum is σ = 10057213800. Its totient is φ = 9945466624.

The previous prime is 10001340203. The next prime is 10001340233. The reversal of 10001340211 is 11204310001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11204310001 = 2131 ⋅5257771.

It is a cyclic number.

It is not a de Polignac number, because 10001340211 - 2³ = 10001340203 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10001340191 and 10001340200.

It is not an unprimeable number, because it can be changed into a prime (10001340281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27936526 + ... + 27936883.

It is an arithmetic number, because the mean of its divisors is an integer number (2514303450).

Almost surely, 2^10001340211 is an apocalyptic number.

10001340211 is a deficient number, since it is larger than the sum of its proper divisors (55873589).

10001340211 is an equidigital number, since it uses as much as digits as its factorization.

10001340211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55873588.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10001340211 its reverse (11204310001), we get a palindrome (21205650212).

The spelling of 10001340211 in words is "ten billion, one million, three hundred forty thousand, two hundred eleven".