10001340281 has 2 divisors, whose sum is σ = 10001340282. Its totient is φ = 10001340280.

The previous prime is 10001340259. The next prime is 10001340301. The reversal of 10001340281 is 18204310001.

It is an a-pointer prime, because the next prime (10001340301) can be obtained adding 10001340281 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9908410681 + 92929600 = 99541^2 + 9640^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10001340281 is a prime.

It is a super-2 number, since 2×10001340281² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10001340581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000670140 + 5000670141.

It is an arithmetic number, because the mean of its divisors is an integer number (5000670141).

Almost surely, 2^10001340281 is an apocalyptic number.

It is an amenable number.

10001340281 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001340281 is an equidigital number, since it uses as much as digits as its factorization.

10001340281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 10001340281 its reverse (18204310001), we get a palindrome (28205650282).

The spelling of 10001340281 in words is "ten billion, one million, three hundred forty thousand, two hundred eighty-one".