10001400123131 has 2 divisors, whose sum is σ = 10001400123132. Its totient is φ = 10001400123130.

The previous prime is 10001400123119. The next prime is 10001400123149. The reversal of 10001400123131 is 13132100410001.

It is a weak prime.

It is an emirp because it is prime and its reverse (13132100410001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10001400123131 is a prime.

It is a super-2 number, since 2×10001400123131² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10001400143131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000700061565 + 5000700061566.

It is an arithmetic number, because the mean of its divisors is an integer number (5000700061566).

Almost surely, 2^{10001400123131} is an apocalyptic number.

10001400123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001400123131 is an equidigital number, since it uses as much as digits as its factorization.

10001400123131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10001400123131 its reverse (13132100410001), we get a palindrome (23133500533132).

The spelling of 10001400123131 in words is "ten trillion, one billion, four hundred million, one hundred twenty-three thousand, one hundred thirty-one".