Base | Representation |
---|---|
bin | 1001000110001011011011… |
… | …1101010011010001010001 |
3 | 1022102011021101112121010212 |
4 | 2101202312331103101101 |
5 | 2302332042331404423 |
6 | 33134424142133505 |
7 | 2051413526035064 |
oct | 221426675232121 |
9 | 38364241477125 |
10 | 10001753388113 |
11 | 32067a1051503 |
12 | 11564a6b81295 |
13 | 5772134a8396 |
14 | 268131d508db |
15 | 12527dd40578 |
hex | 918b6f53451 |
10001753388113 has 2 divisors, whose sum is σ = 10001753388114. Its totient is φ = 10001753388112.
The previous prime is 10001753388061. The next prime is 10001753388227. The reversal of 10001753388113 is 31188335710001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8851267611664 + 1150485776449 = 2975108^2 + 1072607^2 .
It is a cyclic number.
It is not a de Polignac number, because 10001753388113 - 224 = 10001736610897 is a prime.
It is not a weakly prime, because it can be changed into another prime (10001753388713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000876694056 + 5000876694057.
It is an arithmetic number, because the mean of its divisors is an integer number (5000876694057).
Almost surely, 210001753388113 is an apocalyptic number.
It is an amenable number.
10001753388113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001753388113 is an equidigital number, since it uses as much as digits as its factorization.
10001753388113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 10001753388113 in words is "ten trillion, one billion, seven hundred fifty-three million, three hundred eighty-eight thousand, one hundred thirteen".
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