Base | Representation |
---|---|
bin | 11101000111000000001… |
… | …01101100100001000001 |
3 | 10112121200002201010212102 |
4 | 32203200011230201001 |
5 | 112341343123031423 |
6 | 2043252025440145 |
7 | 132155455512653 |
oct | 16434005544101 |
9 | 3477602633772 |
10 | 1000192002113 |
11 | 3561a7345a27 |
12 | 141a16340055 |
13 | 73418cb2665 |
14 | 365a3b466d3 |
15 | 1b03d540c28 |
hex | e8e016c841 |
1000192002113 has 2 divisors, whose sum is σ = 1000192002114. Its totient is φ = 1000192002112.
The previous prime is 1000192002097. The next prime is 1000192002127. The reversal of 1000192002113 is 3112002910001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 697771196929 + 302420805184 = 835327^2 + 549928^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000192002113 - 24 = 1000192002097 is a prime.
It is a super-3 number, since 3×10001920021133 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1000192002163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500096001056 + 500096001057.
It is an arithmetic number, because the mean of its divisors is an integer number (500096001057).
Almost surely, 21000192002113 is an apocalyptic number.
It is an amenable number.
1000192002113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000192002113 is an equidigital number, since it uses as much as digits as its factorization.
1000192002113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1000192002113 its reverse (3112002910001), we get a palindrome (4112194912114).
The spelling of 1000192002113 in words is "one trillion, one hundred ninety-two million, two thousand, one hundred thirteen".
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