Base | Representation |
---|---|
bin | 101110100100110100… |
… | …1011100101010000001 |
3 | 100120011112222211010121 |
4 | 1131021221130222001 |
5 | 3114320040143412 |
6 | 113540512300241 |
7 | 10140404460544 |
oct | 1351151345201 |
9 | 316145884117 |
10 | 100019849857 |
11 | 39466663644 |
12 | 17474541681 |
13 | 957c96c715 |
14 | 4bab94a85b |
15 | 2905d5b107 |
hex | 1749a5ca81 |
100019849857 has 2 divisors, whose sum is σ = 100019849858. Its totient is φ = 100019849856.
The previous prime is 100019849851. The next prime is 100019849861. The reversal of 100019849857 is 758948910001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93797637696 + 6222212161 = 306264^2 + 78881^2 .
It is a cyclic number.
It is not a de Polignac number, because 100019849857 - 23 = 100019849849 is a prime.
It is not a weakly prime, because it can be changed into another prime (100019849851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50009924928 + 50009924929.
It is an arithmetic number, because the mean of its divisors is an integer number (50009924929).
Almost surely, 2100019849857 is an apocalyptic number.
It is an amenable number.
100019849857 is a deficient number, since it is larger than the sum of its proper divisors (1).
100019849857 is an equidigital number, since it uses as much as digits as its factorization.
100019849857 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 52.
The spelling of 100019849857 in words is "one hundred billion, nineteen million, eight hundred forty-nine thousand, eight hundred fifty-seven".
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