Base | Representation |
---|---|
bin | 1001000110001100011001… |
… | …0100110110100000010011 |
3 | 1022102011221100200210222112 |
4 | 2101203012110312200103 |
5 | 2302333104333014422 |
6 | 33134505512255535 |
7 | 2051423106416363 |
oct | 221430624664023 |
9 | 38364840623875 |
10 | 10002011219987 |
11 | 32069136443a6 |
12 | 11565593a15ab |
13 | 577254a30817 |
14 | 2681582a89a3 |
15 | 1252967beee2 |
hex | 918c6536813 |
10002011219987 has 2 divisors, whose sum is σ = 10002011219988. Its totient is φ = 10002011219986.
The previous prime is 10002011219927. The next prime is 10002011220023. The reversal of 10002011219987 is 78991211020001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10002011219987 - 232 = 9997716252691 is a prime.
It is a super-2 number, since 2×100020112199872 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10002011219927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001005609993 + 5001005609994.
It is an arithmetic number, because the mean of its divisors is an integer number (5001005609994).
Almost surely, 210002011219987 is an apocalyptic number.
10002011219987 is a deficient number, since it is larger than the sum of its proper divisors (1).
10002011219987 is an equidigital number, since it uses as much as digits as its factorization.
10002011219987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 41.
Adding to 10002011219987 its reverse (78991211020001), we get a palindrome (88993222239988).
The spelling of 10002011219987 in words is "ten trillion, two billion, eleven million, two hundred nineteen thousand, nine hundred eighty-seven".
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