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100021002019 is a prime number
BaseRepresentation
bin101110100100110110…
…1110101111100100011
3100120011122011100121021
41131021231311330203
53114320334031034
6113540553110311
710140420326611
oct1351155657443
9316148140537
10100021002019
1139467280244
12174749b8397
13957cc83c83
144babb6a6b1
152905ed76b4
hex1749b75f23

100021002019 has 2 divisors, whose sum is σ = 100021002020. Its totient is φ = 100021002018.

The previous prime is 100021001999. The next prime is 100021002031. The reversal of 100021002019 is 910200120001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100021002019 is a prime.

It is a super-2 number, since 2×1000210020192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100021001993 and 100021002011.

It is not a weakly prime, because it can be changed into another prime (100021002619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50010501009 + 50010501010.

It is an arithmetic number, because the mean of its divisors is an integer number (50010501010).

Almost surely, 2100021002019 is an apocalyptic number.

100021002019 is a deficient number, since it is larger than the sum of its proper divisors (1).

100021002019 is an equidigital number, since it uses as much as digits as its factorization.

100021002019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

The spelling of 100021002019 in words is "one hundred billion, twenty-one million, two thousand, nineteen".