Search a number
-
+
100021310083 is a prime number
BaseRepresentation
bin101110100100110111…
…1000001001010000011
3100120011122202000012001
41131021233001022003
53114320423410313
6113541003444431
710140423052012
oct1351157011203
9316148660161
10100021310083
1139467470742
1217474b26717
139580061266
144babc0aa79
152906048add
hex1749bc1283

100021310083 has 2 divisors, whose sum is σ = 100021310084. Its totient is φ = 100021310082.

The previous prime is 100021310057. The next prime is 100021310141. The reversal of 100021310083 is 380013120001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100021310083 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100021310083.

It is not a weakly prime, because it can be changed into another prime (100021310003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50010655041 + 50010655042.

It is an arithmetic number, because the mean of its divisors is an integer number (50010655042).

Almost surely, 2100021310083 is an apocalyptic number.

100021310083 is a deficient number, since it is larger than the sum of its proper divisors (1).

100021310083 is an equidigital number, since it uses as much as digits as its factorization.

100021310083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 100021310083 its reverse (380013120001), we get a palindrome (480034430084).

The spelling of 100021310083 in words is "one hundred billion, twenty-one million, three hundred ten thousand, eighty-three".