Base | Representation |
---|---|
bin | 10010101000010110… |
… | …00110110000110110 |
3 | 221211001202221201011 |
4 | 21110023012300312 |
5 | 130441021211042 |
6 | 4332300222434 |
7 | 502601501521 |
oct | 112413066066 |
9 | 27731687634 |
10 | 10002132022 |
11 | 4272a40913 |
12 | 1b3183aa1a |
13 | c35285a1c |
14 | 6ac559bb8 |
15 | 3d817ea17 |
hex | 2542c6c36 |
10002132022 has 4 divisors (see below), whose sum is σ = 15003198036. Its totient is φ = 5001066010.
The previous prime is 10002132017. The next prime is 10002132037. The reversal of 10002132022 is 22023120001.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 10002131993 and 10002132011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2500533004 + ... + 2500533007.
It is an arithmetic number, because the mean of its divisors is an integer number (3750799509).
Almost surely, 210002132022 is an apocalyptic number.
10002132022 is a deficient number, since it is larger than the sum of its proper divisors (5001066014).
10002132022 is an equidigital number, since it uses as much as digits as its factorization.
10002132022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5001066013.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 10002132022 its reverse (22023120001), we get a palindrome (32025252023).
The spelling of 10002132022 in words is "ten billion, two million, one hundred thirty-two thousand, twenty-two".
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