Base | Representation |
---|---|
bin | 11101000111000101001… |
… | …11100011001110101001 |
3 | 10112121210001112202220112 |
4 | 32203202213203032221 |
5 | 112341440003301101 |
6 | 2043300143104105 |
7 | 132156512246342 |
oct | 16434247431651 |
9 | 3477701482815 |
10 | 1000234431401 |
11 | 356219295757 |
12 | 141a285a2035 |
13 | 73424a19b4a |
14 | 365a962d0c9 |
15 | 1b0421226bb |
hex | e8e29e33a9 |
1000234431401 has 2 divisors, whose sum is σ = 1000234431402. Its totient is φ = 1000234431400.
The previous prime is 1000234431283. The next prime is 1000234431461. The reversal of 1000234431401 is 1041344320001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 984073920025 + 16160511376 = 992005^2 + 127124^2 .
It is an emirp because it is prime and its reverse (1041344320001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1000234431401 - 230 = 999160689577 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000234431461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500117215700 + 500117215701.
It is an arithmetic number, because the mean of its divisors is an integer number (500117215701).
Almost surely, 21000234431401 is an apocalyptic number.
It is an amenable number.
1000234431401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000234431401 is an equidigital number, since it uses as much as digits as its factorization.
1000234431401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1000234431401 its reverse (1041344320001), we get a palindrome (2041578751402).
The spelling of 1000234431401 in words is "one trillion, two hundred thirty-four million, four hundred thirty-one thousand, four hundred one".
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