Base | Representation |
---|---|
bin | 10110101111101000011111… |
… | …110100100101001001110011 |
3 | 111010011210202010212221121201 |
4 | 112233220133310211021303 |
5 | 101102344044440414303 |
6 | 552425143504432031 |
7 | 30032644430455222 |
oct | 2657503764451163 |
9 | 433153663787551 |
10 | 100030322201203 |
11 | 29966692108799 |
12 | b276668618617 |
13 | 43a7a851b0134 |
14 | 1a9b6c9d6ccb9 |
15 | b8704184081d |
hex | 5afa1fd25273 |
100030322201203 has 2 divisors, whose sum is σ = 100030322201204. Its totient is φ = 100030322201202.
The previous prime is 100030322201189. The next prime is 100030322201219. The reversal of 100030322201203 is 302102223030001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100030322201203 is a prime.
It is not a weakly prime, because it can be changed into another prime (100030322271203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50015161100601 + 50015161100602.
It is an arithmetic number, because the mean of its divisors is an integer number (50015161100602).
Almost surely, 2100030322201203 is an apocalyptic number.
100030322201203 is a deficient number, since it is larger than the sum of its proper divisors (1).
100030322201203 is an equidigital number, since it uses as much as digits as its factorization.
100030322201203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 100030322201203 its reverse (302102223030001), we get a palindrome (402132545231204).
The spelling of 100030322201203 in words is "one hundred trillion, thirty billion, three hundred twenty-two million, two hundred one thousand, two hundred three".
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