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10003043131143 = 33334347710381
BaseRepresentation
bin1001000110010000001111…
…0101010001111100000111
31022102021121021102022222020
42101210003311101330013
52302342213020144033
633135200133534223
72051460506465616
oct221440365217407
938367537368866
1010003043131143
1132072a3083537
1211567a6aa4373
1357738a76183a
1426821536187d
151253071a66b3
hex91903d51f07

10003043131143 has 4 divisors (see below), whose sum is σ = 13337390841528. Its totient is φ = 6668695420760.

The previous prime is 10003043131063. The next prime is 10003043131157. The reversal of 10003043131143 is 34113134030001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10003043131143 - 216 = 10003043065607 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10003043131163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1667173855188 + ... + 1667173855193.

It is an arithmetic number, because the mean of its divisors is an integer number (3334347710382).

Almost surely, 210003043131143 is an apocalyptic number.

10003043131143 is a deficient number, since it is larger than the sum of its proper divisors (3334347710385).

10003043131143 is an equidigital number, since it uses as much as digits as its factorization.

10003043131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3334347710384.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 10003043131143 its reverse (34113134030001), we get a palindrome (44116177161144).

The spelling of 10003043131143 in words is "ten trillion, three billion, forty-three million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 3 3334347710381 10003043131143