Base | Representation |
---|---|
bin | 1001000110010000100010… |
… | …0101111101001100111001 |
3 | 1022102021210211201002121112 |
4 | 2101210020211331030321 |
5 | 2302342343442000441 |
6 | 33135212105450105 |
7 | 2051462466405026 |
oct | 221441045751471 |
9 | 38367724632545 |
10 | 10003123000121 |
11 | 3207334175259 |
12 | 11568097a0935 |
13 | 5773a11773a4 |
14 | 268221bd254d |
15 | 12530e1d14eb |
hex | 9190897d339 |
10003123000121 has 2 divisors, whose sum is σ = 10003123000122. Its totient is φ = 10003123000120.
The previous prime is 10003123000103. The next prime is 10003123000141. The reversal of 10003123000121 is 12100032130001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6384895117225 + 3618227882896 = 2526835^2 + 1902164^2 .
It is a cyclic number.
It is not a de Polignac number, because 10003123000121 - 218 = 10003122737977 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10003123000096 and 10003123000105.
It is not a weakly prime, because it can be changed into another prime (10003123000141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001561500060 + 5001561500061.
It is an arithmetic number, because the mean of its divisors is an integer number (5001561500061).
Almost surely, 210003123000121 is an apocalyptic number.
It is an amenable number.
10003123000121 is a deficient number, since it is larger than the sum of its proper divisors (1).
10003123000121 is an equidigital number, since it uses as much as digits as its factorization.
10003123000121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 10003123000121 its reverse (12100032130001), we get a palindrome (22103155130122).
The spelling of 10003123000121 in words is "ten trillion, three billion, one hundred twenty-three million, one hundred twenty-one", and thus it is an aban number.
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