Search a number
-
+
100031320032 = 25371723936637
BaseRepresentation
bin101110100101001010…
…1001100111111100000
3100120012100120120020220
41131022111030333200
53114331004220112
6113542002203040
710140604122360
oct1351225147740
9316170516226
10100031320032
1139472088326
1217478353480
1395821574c7
144bad2949a0
152906d7498c
hex174a54cfe0

100031320032 has 192 divisors, whose sum is σ = 319084738560. Its totient is φ = 26785898496.

The previous prime is 100031320007. The next prime is 100031320057. The reversal of 100031320032 is 230023130001.

It is an interprime number because it is at equal distance from previous prime (100031320007) and next prime (100031320057).

It is a super-3 number, since 3×1000313200323 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100031319993 and 100031320020.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2712018 + ... + 2748654.

It is an arithmetic number, because the mean of its divisors is an integer number (1661899680).

Almost surely, 2100031320032 is an apocalyptic number.

100031320032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100031320032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159542369280).

100031320032 is an abundant number, since it is smaller than the sum of its proper divisors (219053418528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100031320032 is a wasteful number, since it uses less digits than its factorization.

100031320032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36913 (or 36905 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 100031320032 its reverse (230023130001), we get a palindrome (330054450033).

The spelling of 100031320032 in words is "one hundred billion, thirty-one million, three hundred twenty thousand, thirty-two".