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10003233113 is a prime number
BaseRepresentation
bin10010101000011110…
…10011100101011001
3221211010211220010022
421110033103211121
5130441311424423
64332340000225
7502614035636
oct112417234531
927733756108
1010003233113
114273623105
121b32090075
13c3557cc63
146ac76518d
153d82eadc8
hex2543d3959

10003233113 has 2 divisors, whose sum is σ = 10003233114. Its totient is φ = 10003233112.

The previous prime is 10003233103. The next prime is 10003233139. The reversal of 10003233113 is 31133230001.

10003233113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8893810249 + 1109422864 = 94307^2 + 33308^2 .

It is a cyclic number.

It is not a de Polignac number, because 10003233113 - 26 = 10003233049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10003233091 and 10003233100.

It is not a weakly prime, because it can be changed into another prime (10003233103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001616556 + 5001616557.

It is an arithmetic number, because the mean of its divisors is an integer number (5001616557).

Almost surely, 210003233113 is an apocalyptic number.

It is an amenable number.

10003233113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10003233113 is an equidigital number, since it uses as much as digits as its factorization.

10003233113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 10003233113 its reverse (31133230001), we get a palindrome (41136463114).

The spelling of 10003233113 in words is "ten billion, three million, two hundred thirty-three thousand, one hundred thirteen".