Base | Representation |
---|---|
bin | 10010101000011111… |
… | …00110101001011001 |
3 | 221211010222212020011 |
4 | 21110033212221121 |
5 | 130441321424233 |
6 | 4332341401521 |
7 | 502614512401 |
oct | 112417465131 |
9 | 27733885204 |
10 | 10003311193 |
11 | 4273676837 |
12 | 1b321092a1 |
13 | c355a9665 |
14 | 6ac785801 |
15 | 3d83140cd |
hex | 2543e6a59 |
10003311193 has 2 divisors, whose sum is σ = 10003311194. Its totient is φ = 10003311192.
The previous prime is 10003311161. The next prime is 10003311239. The reversal of 10003311193 is 39111330001.
10003311193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8034791769 + 1968519424 = 89637^2 + 44368^2 .
It is a cyclic number.
It is not a de Polignac number, because 10003311193 - 25 = 10003311161 is a prime.
It is not a weakly prime, because it can be changed into another prime (10003311103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001655596 + 5001655597.
It is an arithmetic number, because the mean of its divisors is an integer number (5001655597).
Almost surely, 210003311193 is an apocalyptic number.
It is an amenable number.
10003311193 is a deficient number, since it is larger than the sum of its proper divisors (1).
10003311193 is an equidigital number, since it uses as much as digits as its factorization.
10003311193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 10003311193 its reverse (39111330001), we get a palindrome (49114641194).
The spelling of 10003311193 in words is "ten billion, three million, three hundred eleven thousand, one hundred ninety-three".
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