Base | Representation |
---|---|
bin | 1001000110010011111011… |
… | …1110100100011101001001 |
3 | 1022102101011102120221011101 |
4 | 2101210332332210131021 |
5 | 2302401231032001100 |
6 | 33135442422101401 |
7 | 2051524216021141 |
oct | 221447676443511 |
9 | 38371142527141 |
10 | 10004035422025 |
11 | 3207762211347 |
12 | 1156a2327a861 |
13 | 5774b81ccac8 |
14 | 2682ab063921 |
15 | 12536436386a |
hex | 9193efa4749 |
10004035422025 has 24 divisors (see below), whose sum is σ = 12473901149984. Its totient is φ = 7958809267200.
The previous prime is 10004035422001. The next prime is 10004035422103. The reversal of 10004035422025 is 52022453040001.
It is not a de Polignac number, because 10004035422025 - 225 = 10004001867593 is a prime.
It is a super-3 number, since 3×100040354220253 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10004035421984 and 10004035422002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12678310 + ... + 13444240.
Almost surely, 210004035422025 is an apocalyptic number.
It is an amenable number.
10004035422025 is a deficient number, since it is larger than the sum of its proper divisors (2469865727959).
10004035422025 is a wasteful number, since it uses less digits than its factorization.
10004035422025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 768841 (or 768836 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 28.
Adding to 10004035422025 its reverse (52022453040001), we get a palindrome (62026488462026).
The spelling of 10004035422025 in words is "ten trillion, four billion, thirty-five million, four hundred twenty-two thousand, twenty-five".
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