100041124433 has 2 divisors, whose sum is σ = 100041124434. Its totient is φ = 100041124432.

The previous prime is 100041124387. The next prime is 100041124439. The reversal of 100041124433 is 334421140001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99711955984 + 329168449 = 315772^2 + 18143^2 .

It is a cyclic number.

It is not a de Polignac number, because 100041124433 - 2¹⁸ = 100040862289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100041124399 and 100041124408.

It is not a weakly prime, because it can be changed into another prime (100041124439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50020562216 + 50020562217.

It is an arithmetic number, because the mean of its divisors is an integer number (50020562217).

Almost surely, 2^100041124433 is an apocalyptic number.

It is an amenable number.

100041124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100041124433 is an equidigital number, since it uses as much as digits as its factorization.

100041124433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 100041124433 its reverse (334421140001), we get a palindrome (434462264434).

The spelling of 100041124433 in words is "one hundred billion, forty-one million, one hundred twenty-four thousand, four hundred thirty-three".