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10004113334122 = 25002056667061
BaseRepresentation
bin1001000110010100001110…
…0111110001111101101010
31022102101100212012021110121
42101211003213301331222
52302401411003142442
633135454244033454
72051526153200125
oct221450347617552
938371325167417
1010004113334122
1132077a2196906
121156a4539288a
135774cb3aba3b
142682b75453bc
1512536b103967
hex919439f1f6a

10004113334122 has 4 divisors (see below), whose sum is σ = 15006170001186. Its totient is φ = 5002056667060.

The previous prime is 10004113334119. The next prime is 10004113334123. The reversal of 10004113334122 is 22143331140001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6590151302641 + 3413962031481 = 2567129^2 + 1847691^2 .

It is not an unprimeable number, because it can be changed into a prime (10004113334123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2501028333529 + ... + 2501028333532.

Almost surely, 210004113334122 is an apocalyptic number.

10004113334122 is a deficient number, since it is larger than the sum of its proper divisors (5002056667064).

10004113334122 is an equidigital number, since it uses as much as digits as its factorization.

10004113334122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5002056667063.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10004113334122 its reverse (22143331140001), we get a palindrome (32147444474123).

The spelling of 10004113334122 in words is "ten trillion, four billion, one hundred thirteen million, three hundred thirty-four thousand, one hundred twenty-two".

Divisors: 1 2 5002056667061 10004113334122