Base | Representation |
---|---|
bin | 1001000110010101011100… |
… | …1010100100101111100001 |
3 | 1022102102012201011201020021 |
4 | 2101211113022210233201 |
5 | 2302403043423101423 |
6 | 33135550555513441 |
7 | 2051540244200602 |
oct | 221452712445741 |
9 | 38372181151207 |
10 | 10004441222113 |
11 | 3207950288a18 |
12 | 1156b17158881 |
13 | 5775512c23c0 |
14 | 268308cd7da9 |
15 | 125389cc095d |
hex | 919572a4be1 |
10004441222113 has 32 divisors (see below), whose sum is σ = 11319966483840. Its totient is φ = 8777641797120.
The previous prime is 10004441222093. The next prime is 10004441222129. The reversal of 10004441222113 is 31122214440001.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10004441222113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10004441222813) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8223870 + ... + 9361672.
It is an arithmetic number, because the mean of its divisors is an integer number (353748952620).
Almost surely, 210004441222113 is an apocalyptic number.
10004441222113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10004441222113 is a deficient number, since it is larger than the sum of its proper divisors (1315525261727).
10004441222113 is a wasteful number, since it uses less digits than its factorization.
10004441222113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1138209.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 10004441222113 its reverse (31122214440001), we get a palindrome (41126655662114).
The spelling of 10004441222113 in words is "ten trillion, four billion, four hundred forty-one million, two hundred twenty-two thousand, one hundred thirteen".
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