Base | Representation |
---|---|
bin | 111011101000100… |
… | …101101001010001 |
3 | 2120201121110002012 |
4 | 323220211221101 |
5 | 4022111330242 |
6 | 243140032305 |
7 | 33536034035 |
oct | 7350455121 |
9 | 2521543065 |
10 | 1000495697 |
11 | 473832253 |
12 | 23b092695 |
13 | 12c3819b6 |
14 | 96c3a1c5 |
15 | 5cc7d282 |
hex | 3ba25a51 |
1000495697 has 2 divisors, whose sum is σ = 1000495698. Its totient is φ = 1000495696.
The previous prime is 1000495693. The next prime is 1000495703. The reversal of 1000495697 is 7965940001.
1000495697 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 989479936 + 11015761 = 31456^2 + 3319^2 .
It is an emirp because it is prime and its reverse (7965940001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1000495697 - 22 = 1000495693 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000495693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500247848 + 500247849.
It is an arithmetic number, because the mean of its divisors is an integer number (500247849).
Almost surely, 21000495697 is an apocalyptic number.
It is an amenable number.
1000495697 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000495697 is an equidigital number, since it uses as much as digits as its factorization.
1000495697 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68040, while the sum is 41.
The square root of 1000495697 is about 31630.6132883952. The cubic root of 1000495697 is about 1000.1652050391.
The spelling of 1000495697 in words is "one billion, four hundred ninety-five thousand, six hundred ninety-seven".
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