1000498133 has 4 divisors (see below), whose sum is σ = 1014589728. Its totient is φ = 986406540.

The previous prime is 1000498129. The next prime is 1000498139. The reversal of 1000498133 is 3318940001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3318940001 = 13 ⋅255303077.

It is a cyclic number.

It is not a de Polignac number, because 1000498133 - 2² = 1000498129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1000498096 and 1000498105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000498139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7045691 + ... + 7045832.

It is an arithmetic number, because the mean of its divisors is an integer number (253647432).

Almost surely, 2^1000498133 is an apocalyptic number.

It is an amenable number.

1000498133 is a deficient number, since it is larger than the sum of its proper divisors (14091595).

1000498133 is an equidigital number, since it uses as much as digits as its factorization.

1000498133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14091594.

The product of its (nonzero) digits is 2592, while the sum is 29.

The square root of 1000498133 is about 31630.6517953709. The cubic root of 1000498133 is about 1000.1660167702.

The spelling of 1000498133 in words is "one billion, four hundred ninety-eight thousand, one hundred thirty-three".