1000498129 has 2 divisors, whose sum is σ = 1000498130. Its totient is φ = 1000498128.

The previous prime is 1000498117. The next prime is 1000498139. The reversal of 1000498129 is 9218940001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 545315904 + 455182225 = 23352^2 + 21335^2 .

It is an emirp because it is prime and its reverse (9218940001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000498129 - 2⁷ = 1000498001 is a prime.

It is a super-2 number, since 2×1000498129² = 2001993012265001282, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1000498094 and 1000498103.

It is not a weakly prime, because it can be changed into another prime (1000498139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500249064 + 500249065.

It is an arithmetic number, because the mean of its divisors is an integer number (500249065).

Almost surely, 2^1000498129 is an apocalyptic number.

It is an amenable number.

1000498129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000498129 is an equidigital number, since it uses as much as digits as its factorization.

1000498129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 34.

The square root of 1000498129 is about 31630.6517321411. The cubic root of 1000498129 is about 1000.1660154373.

The spelling of 1000498129 in words is "one billion, four hundred ninety-eight thousand, one hundred twenty-nine".