Base | Representation |
---|---|
bin | 11101000111101010110… |
… | …11100010001011111011 |
3 | 10112122121001102210011222 |
4 | 32203311123202023323 |
5 | 112343111303023012 |
6 | 2043351335542255 |
7 | 132200364042002 |
oct | 16436533421373 |
9 | 3478531383158 |
10 | 1000550048507 |
11 | 356370466539 |
12 | 141ab622a98b |
13 | 73475225129 |
14 | 365d9509c39 |
15 | 1b05ebb8972 |
hex | e8f56e22fb |
1000550048507 has 2 divisors, whose sum is σ = 1000550048508. Its totient is φ = 1000550048506.
The previous prime is 1000550048503. The next prime is 1000550048513. The reversal of 1000550048507 is 7058400550001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1000550048507 - 22 = 1000550048503 is a prime.
It is a super-2 number, since 2×10005500485072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1000550048503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500275024253 + 500275024254.
It is an arithmetic number, because the mean of its divisors is an integer number (500275024254).
Almost surely, 21000550048507 is an apocalyptic number.
1000550048507 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000550048507 is an equidigital number, since it uses as much as digits as its factorization.
1000550048507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28000, while the sum is 35.
Adding to 1000550048507 its reverse (7058400550001), we get a palindrome (8058950598508).
The spelling of 1000550048507 in words is "one trillion, five hundred fifty million, forty-eight thousand, five hundred seven".
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