Base | Representation |
---|---|
bin | 10110110000000100101001… |
… | …111000111010011111111011 |
3 | 111010021200210011212222122111 |
4 | 112300010221320322133323 |
5 | 101103343004301133233 |
6 | 552451103525233151 |
7 | 30035064565502524 |
oct | 2660045170723773 |
9 | 433250704788574 |
10 | 100060555880443 |
11 | 29978497248464 |
12 | b2804a58627b7 |
13 | 43aa892ac2072 |
14 | 1a9cd5744584b |
15 | b87c10c27acd |
hex | 5b0129e3a7fb |
100060555880443 has 2 divisors, whose sum is σ = 100060555880444. Its totient is φ = 100060555880442.
The previous prime is 100060555880423. The next prime is 100060555880599. The reversal of 100060555880443 is 344088555060001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100060555880443 - 233 = 100051965945851 is a prime.
It is a super-3 number, since 3×1000605558804433 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (100060555880423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50030277940221 + 50030277940222.
It is an arithmetic number, because the mean of its divisors is an integer number (50030277940222).
Almost surely, 2100060555880443 is an apocalyptic number.
100060555880443 is a deficient number, since it is larger than the sum of its proper divisors (1).
100060555880443 is an equidigital number, since it uses as much as digits as its factorization.
100060555880443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304000, while the sum is 49.
The spelling of 100060555880443 in words is "one hundred trillion, sixty billion, five hundred fifty-five million, eight hundred eighty thousand, four hundred forty-three".
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