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100060555880443 is a prime number
BaseRepresentation
bin10110110000000100101001…
…111000111010011111111011
3111010021200210011212222122111
4112300010221320322133323
5101103343004301133233
6552451103525233151
730035064565502524
oct2660045170723773
9433250704788574
10100060555880443
1129978497248464
12b2804a58627b7
1343aa892ac2072
141a9cd5744584b
15b87c10c27acd
hex5b0129e3a7fb

100060555880443 has 2 divisors, whose sum is σ = 100060555880444. Its totient is φ = 100060555880442.

The previous prime is 100060555880423. The next prime is 100060555880599. The reversal of 100060555880443 is 344088555060001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100060555880443 - 233 = 100051965945851 is a prime.

It is a super-3 number, since 3×1000605558804433 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (100060555880423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50030277940221 + 50030277940222.

It is an arithmetic number, because the mean of its divisors is an integer number (50030277940222).

Almost surely, 2100060555880443 is an apocalyptic number.

100060555880443 is a deficient number, since it is larger than the sum of its proper divisors (1).

100060555880443 is an equidigital number, since it uses as much as digits as its factorization.

100060555880443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304000, while the sum is 49.

The spelling of 100060555880443 in words is "one hundred trillion, sixty billion, five hundred fifty-five million, eight hundred eighty thousand, four hundred forty-three".