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100095804519433 is a prime number
BaseRepresentation
bin10110110000100101011110…
…110111110011010000001001
3111010102001202201102101011021
4112300211132313303100021
5101104432201424110213
6552515213334032441
730040453230132052
oct2660453667632011
9433361681371137
10100095804519433
1129991435182668
12b2872a24a8721
1343b0cbc69cab8
141aa093c995729
15b88ac551dd8d
hex5b095edf3409

100095804519433 has 2 divisors, whose sum is σ = 100095804519434. Its totient is φ = 100095804519432.

The previous prime is 100095804519427. The next prime is 100095804519437. The reversal of 100095804519433 is 334915408590001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99864585873529 + 231218645904 = 9993227^2 + 480852^2 .

It is a cyclic number.

It is not a de Polignac number, because 100095804519433 - 245 = 64911432430601 is a prime.

It is not a weakly prime, because it can be changed into another prime (100095804519437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50047902259716 + 50047902259717.

It is an arithmetic number, because the mean of its divisors is an integer number (50047902259717).

Almost surely, 2100095804519433 is an apocalyptic number.

It is an amenable number.

100095804519433 is a deficient number, since it is larger than the sum of its proper divisors (1).

100095804519433 is an equidigital number, since it uses as much as digits as its factorization.

100095804519433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2332800, while the sum is 52.

The spelling of 100095804519433 in words is "one hundred trillion, ninety-five billion, eight hundred four million, five hundred nineteen thousand, four hundred thirty-three".