10010009999953 has 2 divisors, whose sum is σ = 10010009999954. Its totient is φ = 10010009999952.

The previous prime is 10010009999947. The next prime is 10010009999981. The reversal of 10010009999953 is 35999990001001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7607485199889 + 2402524800064 = 2758167^2 + 1550008^2 .

It is a cyclic number.

It is not a de Polignac number, because 10010009999953 - 2²¹ = 10010007902801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10010009999894 and 10010009999903.

It is not a weakly prime, because it can be changed into another prime (10010009999153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005004999976 + 5005004999977.

It is an arithmetic number, because the mean of its divisors is an integer number (5005004999977).

Almost surely, 2^{10010009999953} is an apocalyptic number.

It is an amenable number.

10010009999953 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010009999953 is an equidigital number, since it uses as much as digits as its factorization.

10010009999953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 885735, while the sum is 55.

The spelling of 10010009999953 in words is "ten trillion, ten billion, nine million, nine hundred ninety-nine thousand, nine hundred fifty-three".