100100200120213 has 4 divisors (see below), whose sum is σ = 100113817349728. Its totient is φ = 100086582890700.

The previous prime is 100100200120139. The next prime is 100100200120273. The reversal of 100100200120213 is 312021002001001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100100200120213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100100200120193 and 100100200120202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100100200120273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6808603731 + ... + 6808618432.

It is an arithmetic number, because the mean of its divisors is an integer number (25028454337432).

Almost surely, 2^{100100200120213} is an apocalyptic number.

It is an amenable number.

100100200120213 is a deficient number, since it is larger than the sum of its proper divisors (13617229515).

100100200120213 is an equidigital number, since it uses as much as digits as its factorization.

100100200120213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13617229514.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 100100200120213 its reverse (312021002001001), we get a palindrome (412121202121214).

The spelling of 100100200120213 in words is "one hundred trillion, one hundred billion, two hundred million, one hundred twenty thousand, two hundred thirteen".