10010100000041 has 2 divisors, whose sum is σ = 10010100000042. Its totient is φ = 10010100000040.

The previous prime is 10010099999989. The next prime is 10010100000077. The reversal of 10010100000041 is 14000000101001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9973090320400 + 37009679641 = 3158020^2 + 192379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10010100000041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10010099999974 and 10010100000028.

It is not a weakly prime, because it can be changed into another prime (10010100060041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005050000020 + 5005050000021.

It is an arithmetic number, because the mean of its divisors is an integer number (5005050000021).

Almost surely, 2^{10010100000041} is an apocalyptic number.

It is an amenable number.

10010100000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010100000041 is an equidigital number, since it uses as much as digits as its factorization.

10010100000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 10010100000041 its reverse (14000000101001), we get a palindrome (24010100101042).

The spelling of 10010100000041 in words is "ten trillion, ten billion, one hundred million, forty-one", and thus it is an aban number.