100101011010113 has 2 divisors, whose sum is σ = 100101011010114. Its totient is φ = 100101011010112.

The previous prime is 100101011010107. The next prime is 100101011010211. The reversal of 100101011010113 is 311010110101001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99996160036864 + 104850973249 = 9999808^2 + 323807^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100101011010113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100101011010094 and 100101011010103.

It is not a weakly prime, because it can be changed into another prime (100101011040113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050505505056 + 50050505505057.

It is an arithmetic number, because the mean of its divisors is an integer number (50050505505057).

Almost surely, 2^{100101011010113} is an apocalyptic number.

It is an amenable number.

100101011010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100101011010113 is an equidigital number, since it uses as much as digits as its factorization.

100101011010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 100101011010113 its reverse (311010110101001), we get a palindrome (411111121111114).

The spelling of 100101011010113 in words is "one hundred trillion, one hundred one billion, eleven million, ten thousand, one hundred thirteen".