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100101120112022 = 250050560056011
BaseRepresentation
bin10110110000101010011011…
…101101001011010110010110
3111010102120111011122110100212
4112300222123231023112112
5101110024043222041042
6552521453021405422
730041032034000411
oct2660523355132626
9433376434573325
10100101120112022
1129993712743a97
12b288326709872
1343b1658a28763
141aa0cc4928b78
15b88cd7014482
hex5b0a9bb4b596

100101120112022 has 4 divisors (see below), whose sum is σ = 150151680168036. Its totient is φ = 50050560056010.

The previous prime is 100101120111997. The next prime is 100101120112033. The reversal of 100101120112022 is 220211021101001.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 100101120111988 and 100101120112006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025280028004 + ... + 25025280028007.

It is an arithmetic number, because the mean of its divisors is an integer number (37537920042009).

Almost surely, 2100101120112022 is an apocalyptic number.

100101120112022 is a deficient number, since it is larger than the sum of its proper divisors (50050560056014).

100101120112022 is an equidigital number, since it uses as much as digits as its factorization.

100101120112022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50050560056013.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 100101120112022 its reverse (220211021101001), we get a palindrome (320312141213023).

The spelling of 100101120112022 in words is "one hundred trillion, one hundred one billion, one hundred twenty million, one hundred twelve thousand, twenty-two".

Divisors: 1 2 50050560056011 100101120112022