Base | Representation |
---|---|
bin | 10010101001010011… |
… | …00110111100011001 |
3 | 221211121211012100011 |
4 | 21110221212330121 |
5 | 131000043100103 |
6 | 4333143441521 |
7 | 503026454044 |
oct | 112451467431 |
9 | 27747735304 |
10 | 10010128153 |
11 | 4277502493 |
12 | 1b344562a1 |
13 | c36b2546c |
14 | 6ad63bc5b |
15 | 3d8c0dd6d |
hex | 254a66f19 |
10010128153 has 2 divisors, whose sum is σ = 10010128154. Its totient is φ = 10010128152.
The previous prime is 10010128133. The next prime is 10010128211. The reversal of 10010128153 is 35182101001.
10010128153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9905822784 + 104305369 = 99528^2 + 10213^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10010128153 is a prime.
It is not a weakly prime, because it can be changed into another prime (10010128133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005064076 + 5005064077.
It is an arithmetic number, because the mean of its divisors is an integer number (5005064077).
Almost surely, 210010128153 is an apocalyptic number.
It is an amenable number.
10010128153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010128153 is an equidigital number, since it uses as much as digits as its factorization.
10010128153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 10010128153 its reverse (35182101001), we get a palindrome (45192229154).
The spelling of 10010128153 in words is "ten billion, ten million, one hundred twenty-eight thousand, one hundred fifty-three".
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