Base | Representation |
---|---|
bin | 10110110000101011010110… |
… | …110101011000110011110011 |
3 | 111010102200001022021200112222 |
4 | 112300223112311120303303 |
5 | 101110033111200320201 |
6 | 552522135255511255 |
7 | 30041065440634166 |
oct | 2660532665306363 |
9 | 433380038250488 |
10 | 100102112120051 |
11 | 299940816a9338 |
12 | b28856298852b |
13 | 43b17863c8062 |
14 | 1aa0d7a595add |
15 | b88d4416791b |
hex | 5b0ad6d58cf3 |
100102112120051 has 2 divisors, whose sum is σ = 100102112120052. Its totient is φ = 100102112120050.
The previous prime is 100102112119991. The next prime is 100102112120057. The reversal of 100102112120051 is 150021211201001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100102112120051 - 214 = 100102112103667 is a prime.
It is a super-2 number, since 2×1001021121200512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100102112120057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50051056060025 + 50051056060026.
It is an arithmetic number, because the mean of its divisors is an integer number (50051056060026).
Almost surely, 2100102112120051 is an apocalyptic number.
100102112120051 is a deficient number, since it is larger than the sum of its proper divisors (1).
100102112120051 is an equidigital number, since it uses as much as digits as its factorization.
100102112120051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 100102112120051 its reverse (150021211201001), we get a palindrome (250123323321052).
The spelling of 100102112120051 in words is "one hundred trillion, one hundred two billion, one hundred twelve million, one hundred twenty thousand, fifty-one".
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