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10010220013 = 31322910323
BaseRepresentation
bin10010101001010011…
…11101010111101101
3221211121222212100101
421110221331113231
5131000104020023
64333145431101
7503030315623
oct112451752755
927747885311
1010010220013
114277565502
121b3449b491
13c36b58211
146ad663513
153d8c2b1ad
hex254a7d5ed

10010220013 has 4 divisors (see below), whose sum is σ = 10333130368. Its totient is φ = 9687309660.

The previous prime is 10010219981. The next prime is 10010220049. The reversal of 10010220013 is 31002201001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31002201001 = 145932124457.

It is not a de Polignac number, because 10010220013 - 25 = 10010219981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10010220413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161455131 + ... + 161455192.

It is an arithmetic number, because the mean of its divisors is an integer number (2583282592).

Almost surely, 210010220013 is an apocalyptic number.

It is an amenable number.

10010220013 is a deficient number, since it is larger than the sum of its proper divisors (322910355).

10010220013 is an equidigital number, since it uses as much as digits as its factorization.

10010220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 322910354.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 10010220013 its reverse (31002201001), we get a palindrome (41012421014).

The spelling of 10010220013 in words is "ten billion, ten million, two hundred twenty thousand, thirteen".

Divisors: 1 31 322910323 10010220013