100102201112113 has 4 divisors (see below), whose sum is σ = 100205292978288. Its totient is φ = 99999109245940.

The previous prime is 100102201112057. The next prime is 100102201112161. The reversal of 100102201112113 is 311211102201001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100102201112113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100102201112213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51545931631 + ... + 51545933572.

It is an arithmetic number, because the mean of its divisors is an integer number (25051323244572).

Almost surely, 2^{100102201112113} is an apocalyptic number.

It is an amenable number.

100102201112113 is a deficient number, since it is larger than the sum of its proper divisors (103091866175).

100102201112113 is an equidigital number, since it uses as much as digits as its factorization.

100102201112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103091866174.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 100102201112113 its reverse (311211102201001), we get a palindrome (411313303313114).

The spelling of 100102201112113 in words is "one hundred trillion, one hundred two billion, two hundred one million, one hundred twelve thousand, one hundred thirteen".