Base | Representation |
---|---|
bin | 10110110000101100010011… |
… | …100101010011001111101011 |
3 | 111010102202200100002001121211 |
4 | 112300230103211103033223 |
5 | 101110042203104010011 |
6 | 552522424344413551 |
7 | 30041132624633452 |
oct | 2660542345231753 |
9 | 433382610061554 |
10 | 100103131313131 |
11 | 29994554a41171 |
12 | b2887a81772b7 |
13 | 43b18b95c529b |
14 | 1aa1035a9bb99 |
15 | b88da388ab21 |
hex | 5b0b139533eb |
100103131313131 has 2 divisors, whose sum is σ = 100103131313132. Its totient is φ = 100103131313130.
The previous prime is 100103131313071. The next prime is 100103131313189. The reversal of 100103131313131 is 131313131301001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100103131313131 is a prime.
It is a super-2 number, since 2×1001031313131312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100103131313531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50051565656565 + 50051565656566.
It is an arithmetic number, because the mean of its divisors is an integer number (50051565656566).
Almost surely, 2100103131313131 is an apocalyptic number.
100103131313131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100103131313131 is an equidigital number, since it uses as much as digits as its factorization.
100103131313131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 100103131313131 its reverse (131313131301001), we get a palindrome (231416262614132).
The spelling of 100103131313131 in words is "one hundred trillion, one hundred three billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •