Base | Representation |
---|---|
bin | 1001000110101011011011… |
… | …1101010000010001000011 |
3 | 1022102222110000222212021212 |
4 | 2101222312331100101003 |
5 | 2303002140341413103 |
6 | 33142404354040335 |
7 | 2052136432132232 |
oct | 221526675202103 |
9 | 38388400885255 |
10 | 10010343310403 |
11 | 320a3a9914237 |
12 | 11580a38790ab |
13 | 577c81cc9037 |
14 | 268708adab19 |
15 | 1255d30177d8 |
hex | 91ab6f50443 |
10010343310403 has 2 divisors, whose sum is σ = 10010343310404. Its totient is φ = 10010343310402.
The previous prime is 10010343310393. The next prime is 10010343310417. The reversal of 10010343310403 is 30401334301001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10010343310403 - 28 = 10010343310147 is a prime.
It is not a weakly prime, because it can be changed into another prime (10010343310433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005171655201 + 5005171655202.
It is an arithmetic number, because the mean of its divisors is an integer number (5005171655202).
Almost surely, 210010343310403 is an apocalyptic number.
10010343310403 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010343310403 is an equidigital number, since it uses as much as digits as its factorization.
10010343310403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 10010343310403 its reverse (30401334301001), we get a palindrome (40411677611404).
The spelling of 10010343310403 in words is "ten trillion, ten billion, three hundred forty-three million, three hundred ten thousand, four hundred three".
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