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100105425151 = 5711315113331
BaseRepresentation
bin101110100111010111…
…1111001000011111111
3100120101112000111100221
41131032233321003333
53120003442101101
6113553210402211
710142464034314
oct1351657710377
9316345014327
10100105425151
11394aa9a2626
1217499130367
1395946026a4
144bb9064d0b
15290d611aa1
hex174ebf90ff

100105425151 has 8 divisors (see below), whose sum is σ = 100295889408. Its totient is φ = 99915015000.

The previous prime is 100105425143. The next prime is 100105425169. The reversal of 100105425151 is 151524501001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100105425151 - 23 = 100105425143 is a prime.

It is a super-2 number, since 2×1001054251512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100105425451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7502556 + ... + 7515886.

It is an arithmetic number, because the mean of its divisors is an integer number (12536986176).

Almost surely, 2100105425151 is an apocalyptic number.

100105425151 is a deficient number, since it is larger than the sum of its proper divisors (190464257).

100105425151 is a wasteful number, since it uses less digits than its factorization.

100105425151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27053.

The product of its (nonzero) digits is 1000, while the sum is 25.

Adding to 100105425151 its reverse (151524501001), we get a palindrome (251629926152).

The spelling of 100105425151 in words is "one hundred billion, one hundred five million, four hundred twenty-five thousand, one hundred fifty-one".

Divisors: 1 571 13151 13331 7509221 7612001 175315981 100105425151